| To: | <antennaware@contesting.com> |
|---|---|
| Subject: | [Antennaware] Cylindrical Model for Triangular Tower |
| From: | btippett@alum.mit.edu (Bill Tippett) |
| Date: | Tue, 21 May 2002 14:09:54 +0100 |
Somewhere I got the following formula for a cylindrical
equivalent to triangular tower like Rohn 45.
Equivalent Cylindrical Diameter = 2 * CUBEROOT [(D * F^2)/2]
where D = tube diameter and F = Face width. For Rohn 45, D = 1.25"
and F = 18", so cylindrical diameter equivalent = 11.7446"
Does anyone know where this came from or if it is valid?
73, Bill W4ZV
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