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Re: [TenTec] ot

To: N4YG <n4yg@comcast.net>,Discussion of Ten-Tec Equipment <tentec@contesting.com>
Subject: Re: [TenTec] ot
From: "John T. Turner" <jtturner@mac.com>
Reply-to: Discussion of Ten-Tec Equipment <tentec@contesting.com>
Date: Wed, 9 Jan 2008 17:53:54 -0600
List-post: <mailto:tentec@contesting.com>
I think WPM would be equal to Dashes Per Second/0.8 rather than /1.2,  
since the standard dash to dot ratio is 3:1.

John ND0N


On 09 Jan 2008, at 1746, N4YG wrote:

> You will find that there are several methods of specifying CW  
> speed. I use the definition that you will find in ARRL handbooks,  
> the current one and those dating back several 10's of years. It is  
> quite simple
>
> Words Per Minute(WPM) = Dots Per Second / 2.4
>
> This assumes that the duration of dashes is 3 times the duration of  
> a dot and that the duration of a space is the same as the duration  
> of a dash.
>
> It follows then that the speed can also be found from the number of  
> dashes per second
>
> WPM = Dashes Per Second /1.2
>
> So if you want to find the speed, send a string of dashes and count  
> the number in a 5-second period and divide that number by 6.
>
> Joe, N4YG
>
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