- 21. No subject (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Sat, 28 Jul 2001 08:18:30 +0000
- Paul, You sound like an Asshole plain and simple! Billy _________________________________________________________________ Get your FREE download of MSN Explorer at http://explorer.msn.com/intl.asp --
- /archives//html/Amps/2001-07/msg00334.html (6,473 bytes)
- 22. [AMPS] HF Power Divider/Combiner (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Sat, 09 Jun 2001 01:01:16 -0000
- Greetings, Are you wanting to divide into two parts or more? I have tried all of the splitter/combiners in the Motorola RF device apnotes. I do not have access to my library at this time as it is in
- /archives//html/Amps/2001-06/msg00078.html (9,339 bytes)
- 23. [AMPS] RMS Power (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 28 Jun 2001 04:16:26 -0000
- Hey guys, I am having quite a debate with a group of hams and cb'ers about the subject of RMS power. I have been a Ham for almost 44 years and have never had anyone deny that there is such a thing as
- /archives//html/Amps/2001-06/msg00300.html (9,171 bytes)
- 24. [AMPS] RMS Power (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 28 Jun 2001 05:32:16 -0000
- [WC6W] The Bird 43 (without a peak reading module) is an average reading meter. [Billy] I thought that the Bird 43 was an RMS meter without the peak reading module. RMS and average are not the same?
- /archives//html/Amps/2001-06/msg00302.html (8,015 bytes)
- 25. [AMPS] RMS Power (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 28 Jun 2001 15:42:24 -0000
- Ok, then what your saying is that E rms squared/R=Average Power. If that is so, and as one post said Average Power = appx .9 X RMS Power then Average power/.9 should = RMS Power. Also then, what does
- /archives//html/Amps/2001-06/msg00309.html (11,693 bytes)
- 26. [AMPS] RMS Power (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 28 Jun 2001 16:00:39 -0000
- Yeah, I have no problem with what you are saying, but what Bill said about the audio industry inventing RMS has weight in that area. However, I used the term RMS power before the big audio boom start
- /archives//html/Amps/2001-06/msg00312.html (13,319 bytes)
- 27. [AMPS] RMS POWER (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Fri, 29 Jun 2001 04:31:05 -0000
- Yeah, I guess your right Bill. ENOUGH! I have not made myself clear and it is probably my fault. The below is standard stuff that I knew and have been teaching for 30 years. It still does not answer
- /archives//html/Amps/2001-06/msg00323.html (12,602 bytes)
- 28. [AMPS] RMS POWER (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Fri, 29 Jun 2001 18:12:03 -0000
- I do want to add one little thing. If you are doing a COMPLETE computation of the RMS, you do use the 360 degrees. The formula starts with E sub 1 not E sub Zero, That is the Square Root of the sum o
- /archives//html/Amps/2001-06/msg00328.html (14,593 bytes)
- 29. [AMPS] RMS POWER (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Fri, 29 Jun 2001 18:12:47 -0000
- Bill, Do you work with the ARRL? Billy _________________________________________________________________ Get your FREE download of MSN Explorer at http://explorer.msn.com -- FAQ on WWW: http://www.co
- /archives//html/Amps/2001-06/msg00329.html (7,562 bytes)
- 30. No subject (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Sat, 30 Jun 2001 02:49:01 -0000
- <html><DIV>Billy, If you are doing a complete calculation of RMS, you start at E sub zero and end at E infinity-1. The closed form solution is an integral where each interval in the summation is infi
- /archives//html/Amps/2001-06/msg00339.html (8,024 bytes)
- 31. [AMPS] F. S. AMP (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Sat, 30 Jun 2001 11:30:03 -0700
- --=_NextPart_001_0004_01C10158.013E6260 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable This letter did not come through at allI--it was just jibberish made
- /archives//html/Amps/2001-06/msg00340.html (8,953 bytes)
- 32. [AMPS] Conjugate Matching In Class B and C Amplifiers (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Tue, 15 May 2001 21:46:26 -0000
- Linear Amplifiers may or may not be conjugately matched. For maximum power transfer to occur both in and out, and for the amplifier to be unconditionally stable, there must be a simultaneous conjugat
- /archives//html/Amps/2001-05/msg00292.html (11,852 bytes)
- 33. [AMPS] Conjugate Matching In Class B and C Amplifiers (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Wed, 16 May 2001 14:51:58 -0000
- To: <amps@contesting.com> I was not taking minimum noise figure into the context of what I said. I am willing to learn. I purposely mismatch for best noise figure. in low-level stages, also. However
- /archives//html/Amps/2001-05/msg00308.html (13,419 bytes)
- 34. [AMPS] Conjugate Matching In Class B and C Amplifiers (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 17 May 2001 15:42:00 -0000
- Thanks for your words! I am not the least in disagreement with what you are saying. I would have to look at the wording that I used originally in my post. I meant to say that a simultaneous conjugate
- /archives//html/Amps/2001-05/msg00334.html (11,603 bytes)
- 35. [AMPS] Conjugate Matching and Efficiency (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 17 May 2001 16:01:51 -0000
- I don't have the time today to re-read and study your statements but I think that I am following you. However, just a quick thought. Suppose the amp is 100% efficient. (We all know that it cannot be!
- /archives//html/Amps/2001-05/msg00335.html (15,041 bytes)
- 36. [AMPS] Conjugate Matching and Efficiency (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Thu, 24 May 2001 15:09:04 -0000
- Hi John, I just had to skim your thesis. I am at the library and only have 30 minutes time to use the internet. My phone is not in yet at the shop. I see your point but I will read the thesis and stu
- /archives//html/Amps/2001-05/msg00407.html (17,535 bytes)
- 37. [AMPS] Conjugate Matching and Efficiency (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Fri, 25 May 2001 16:09:10 -0000
- Greetings Jon, Again, I must admit that I only have time to skim. There are folks waiting to use this computer and I have bout 9 minutes. JOHN: At the 3 dB points, half the power that is transmitted
- /archives//html/Amps/2001-05/msg00432.html (11,139 bytes)
- 38. [AMPS] Conjugate Matching and Efficiency (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Fri, 25 May 2001 17:17:29 -0000
- By the way Jon, I forgot to mention in the last letter that when I was originally talking about the 3db down point and the calculations, I was not thinking straight and I was confusing the voltage di
- /archives//html/Amps/2001-05/msg00433.html (13,370 bytes)
- 39. [AMPS] Conjugate Matching and Efficiency (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Fri, 25 May 2001 17:30:28 -0000
- STEVE: For power to be reflected, doesn't the source have to be a transmission line? A series C can reduce the power delivered to a load just by adding reactance and increasing the overall impedance
- /archives//html/Amps/2001-05/msg00434.html (11,862 bytes)
- 40. [AMPS] Parallel coaxial feedline For 1/2 Characteristic Impedance (score: 1)
- Author: billydeanward@hotmail.com (Billy Ward)
- Date: Sun, 17 Dec 2000 05:03:57 -0000
- Greetings Group, I would like to have this group's input on something that I have been working on today. Today was not the first time that I've toyed with this idea but I performed the experiments ag
- /archives//html/Amps/2000-12/msg00252.html (9,904 bytes)
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