I have a SK550 (918) zener diode that I believe to be rated at 12VDC @
50W. There appears to be ( barely visible) an arrow pointing away from
the metal threaded housing towards the cathode end. When tested with the
VOM on the diode scale, it conducts (value of 770) with the negative
(black) lead on the metal base and the positive lead on the insulated
end. No meter indication when the leads are reversed. So far so good!
What concerns me is that I checked it with another Western Electric
zener diode clearly identified with numbers and symbols and the
positions of the two VOM leads must be reversed in order to get it to
show a value. In this test, the red lead (+) is on the base and the
negative lead is on the output end ( direction of arrow ) . This
particular 50w zener was working fine on a two hole 8877 I built some
time ago;however, I pulled the zener to do some extensive bias rewiring
and cannot recall how it was originally wired. The question is basically
which orientation should I use. Follow the arrow or reverse the diode and
follow the wiring scheme dictated by the VOM . Is there anyone familiar
with the SK550 in order to:
A. verify its identification?
b. help get the orientation correct?
For obvious reasons, I'd rather not use the cut and try approach. Any
help would be appreciated. Dealing with lots of power so I want to ensure
I get it right the first time. Ron W2CQM/3
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