I submit - admittedly without PhD-level academic documentation but based on
hands-on experience - that if the cathode network isn't resonant at or
fairly near the operating frequency there's no "flywheel." With no flywheel
(a) the input impedance is highly non-linear - much like a series rectifier
and resistor/capacitor combination - and (b) the cathode voltage waveform
has very high odd harmonic content.
The anode load seen by the harmonic components is largely reactive, so the
harmonic components of rf plate current contribute only to plate
dissipation, correspondingly reducing plate efficiency at the fundamental
frequency. The magnitude of this effect varies with the exciter and the
length of drive cable, but typically a g.g. amp that delivers ~65%
efficiency with a resonant cathode network of Q 2-4 may drop as low as 50%
efficiency with an untuned input, or with any LC input network/filter of
effective Q </= ~1.
These comments are based on practical observations, but I believe they're
fully consistent with what one would expect based on circuit theory.
73, Dick W0ID
-----Original Message-----
From: John / NS1Z [SMTP:ns1z@agate.net]
Sent: Friday, August 28, 1998 4:27 AM
To: Rich Measures
Cc: amps@contesting.com
Subject: Re: [AMPS] Low Output on 10 meters
OK, time for amps 101 again:
I'll concede the pi is back to back Ls but, if it is not resonant at the
operating frequency, what is it that everyone is tuning it to....
At 02:27 AM 8/28/98 -0800, Rich Measures wrote:
>
>A pi-network is two L-networks in series. It is not resonant at the
>operating frequency
>>_______________________________________________________________
John Wilcox NS1Z
FN44rn
ns1z@agate.net
fon: 207-364-2246
871 Route 120
Rumford, ME 04276-3836
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