>
> In a PI-L output network, is the RF current the same or different in the PI
>inductor (L1) and the L inductor (L2) ?
> On the one hand, it would seem that the currents would be the same since
>the inductors are in series. However on the other hand, since the network
>is a
>stepdown impedance transformer, it would seem that the current in L2 would be
>greater than in L1 due to the transformer action.
> In most of the amp designs that I have seen, the 10 meter portion of L1
>typically is 1/4" tubing and the 10 meter portion of L2 is #12 gauge wire.
> If the current is the same or greater in L2, why shouldn't the conductor
>of L2 be at least as large or larger than that of L1 ?
? The circulating current in L1, the main tank coil is approx
anode-current x Q (typ. 11A-rms). The current in L2 is the same as the
current in the 50-ohm load. (typ 5.5A-rms).
> Thanks to anyone who can clear this up for me.
> 73 Don K9MUF
>
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>
Rich...
R. L. Measures, 805-386-3734, AG6K, www.vcnet.com/measures
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