On Tue, 9 Feb 1999 15:35:42 -0600 "Roy Koeppe" <royanjoy@ncn.net> writes:
>
>HI,
>
>L1 has much greater, internal circulating currents than L2 has. With
>typical
>loaded Q's, L1 could easily have ten times the current of L2.
>
>73, K6XK
Not likely. If the 50 Ohm current is 5-6A then there would not be any ham
amps produced that would survive with 50-60A in L1. I would guess 2-3
times would be more in line with a good design.
In my experience with PI-L's it is a voltage breakdown and not current
heating that destroys many bandswitches.
73 Carl KM1H
>
>
>-----Original Message-----
>From: JWebs3939@aol.com <JWebs3939@aol.com>
>To: amps@contesting.com <amps@contesting.com>
To: <amps@contesting.com>
>Date: Tuesday, February 09, 1999 3:14 PM
>Subject: [AMPS] PI-L network inductor wire sizes
>
>
>>
>> In a PI-L output network, is the RF current the same or different
>in the
>PI
>>inductor (L1) and the L inductor (L2) ?
>> On the one hand, it would seem that the currents would be the
>same
>since
>>the inductors are in series. However on the other hand, since the
>network
>is a
>>stepdown impedance transformer, it would seem that the current in L2
>would
>be
>>greater than in L1 due to the transformer action.
>> In most of the amp designs that I have seen, the 10 meter portion
>of L1
>>typically is 1/4" tubing and the 10 meter portion of L2 is #12 gauge
>wire.
>> If the current is the same or greater in L2, why shouldn't the
>conductor
>>of L2 be at least as large or larger than that of L1 ?
>> Thanks to anyone who can clear this up for me.
>> 73 Don K9MUF
>>
>>--
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>>
>
>
>--
>FAQ on WWW: http://www.contesting.com/ampfaq.html
>Submissions: amps@contesting.com
>Administrative requests: amps-REQUEST@contesting.com
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>
>
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