Rich Measures wrote:
> Carl said:
> >Which is why 100K is the suggested max in any literature I have seen for
> ? References, please. . In a typical 8171 anode-supply, a 100k-ohm
> bleeder would dissipate 810 watts.
> >>>>If I wanted a Reliable bleeder for a 4kV C-filter supply, I would
> >>>>series up 8 to 10 Matsushita/Panasonic 100k-ohm, 3w MOF resistors on a
> piece of
> >>>>perfboard and be done with it.
> >>>Absolute YUK ! 800K to 1M bleders..no way Jose.
> >>Ä What is to be gained by using a 200k-ohm bleeder on a C-filter, Carl?
> >Quicker HV bleed down time, less chance of a recharge.
> ? What mechanism recharges the capacitor?
> > All my concerns are safety related and for others not well versed in PS
> >A string of 3W does not offer much of a voltage breakdown safety margin.
> >Matsushita not a common distributor item and similar wattage Panasonic,
> >etc are only 350V.
> ? The manufacturer's (Panasonic/Matsushita) rating at 70 deg. C ambient
> is 500v or 3w . For a 100k-ohm unit, the realizable dissipation is 2.5w
> at 500v. .
The primary purpose of a bleeder in the power supply for my typical
amateur amplifier is *not* for voltage regulation but to allow the
voltage to bleed off of the filter capacitor. A good rule of thumb is
100 ohms per volt, ie. for a 4500 volt supply, the bleeder would be 450k
ohms or thereabouts. Using ohms law, the current through the bleeder
would be 4500/450000 = 0.01 amps. The power rating of the resistor
would then be 4500 x 0.01 = 45 watts. Since safety is the primary
concern with the bleeder, I would be inclined to use a power rating of
100 watts or more. From a practical standpoint I would be inclined to
use 5 series connected 100k 25w resistors. However, the only truly safe
bleeder is a big shorting bar on the end of a very long non-conductive
stick, with ear-plugs inserted in your lug-holes, just in case...
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