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[AMPS] Impedance of amplifiers

To: <amps@contesting.com>
Subject: [AMPS] Impedance of amplifiers
From: measures@vc.net (Rich Measures)
Date: Sun, 18 Jul 1999 00:45:31 -0700


>
>> >  > since 1995, the Handbook has had an inaccurate method of calculating
>> >  > RF current in a DC blocking cap.  My guess is that it will remain there
>> >> until sometime around 2040.  .  
>> >
>> >What is the correct method?
>> 
>> ? Calculate  the difference between instantaneous anode potential at max.
>> conduction and anode supply potential.  Divide by 2^0.5 to convert peak v
>> to RMS v. .
>
>OK, you found the RMS anode voltage for a sinewave at the anode.
>
> > Disconnect the C1 side of the blocking cap.  Measure anode-C.
>> with tube in socket  Calculate capacitive-reactance in ohms. 
>> Current=volts/ohms.    
>
>I'm sorry Rich, something appears to be seriously missing in your 
>"improved" method.
>
?  indeed.  .  .  and the missing something is assumption.  

>You have determined anode RMS voltage, and then assumed that 
>voltage drives the anode capacitance of the tube and that is the 
>current through the blocking cap.
>
>Let's try the "improved" method with a 3CX1200.
>
>Let's assume the RMS voltage is 3000 volts. The anode 
>capacitance is about 14 pF. 

?  Let's not.  To accurately calculate peak and RMS anode-potential, it 
is a mistake to assume that all tube types have the same minimum anode 
potential at max. conduction. 
>.......
-  later, Tom


Rich...

R. L. Measures, 805-386-3734, AG6K, www.vcnet.com/measures  


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