> When I model a series L, the results also show an increase in Q,
> by a lot more than with the series cap. But, there's a lot of options for
> values. After hunting around for a while and not finding a mix that
> works, suggestions are welcome.
With the series L, make it an L network with zero j output.
The tube Cout becomes the L networks shunt component, while
the L "feeds out" to the outside world.
Now take whatever impedance you wind up with and use another
minimum-Q network to transform that back to 50 ohms.
In many (but not all) cases that will result in the lowest Q solution
that provides acceptable harmonic suppression.
73, Tom W8JI
w8ji@contesting.com
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