On 8/1/06 at 6:21 PM Nat Gurumoorthy wrote:
>Hi,
> I am in the process of scrounging together parts for a linear
>amp. I have a pair of GI-7BT. I have acquired a Triad P-14A (115
>primary, 1780V 250ma CCS secondary) Weighs about 14lbs. Secondary
>resistance seems to be about 160 ohms. If I full wave rectify it I
>should get a noload voltage of about 2.6Kv. I have 9 470uf 450V
>105degree CDE electrolytic caps. Maybe I don't have to use all of them?
>With the secondary being 160 ohms will I need step start circuitry to
>limit the inrush current to the capacitors?
Generally, the power supply formula to find out the final DC current the supply
is capable of is to multiply the AC rms current by 0.62 or Iac x 0.62 for a full
wave bridge. That would give 0.25 x 0.62 = 0.155 A available to use. That's
the power supply formula most all transformer manufacturers give. You would
have then about 2517 Vdc at 155 mA available to use at no load. With load
you can figure a drop of about 12% to 13% in voltage, or that's the figure I
always use. 2517 x 0.155 = 390 watts. I think you need a little more umph
than that.
> My mode of operation is going to be SSB. How much power could I
>squeeze out of this transformer. I am going to design this to be a
>class-B amp. My bias point is going to be at the tube cutoff voltage.
>Looking at the PDF file available online it looks to be -45v. It will be
>a GG design with tuned input.
>
>Regards
>Nat AB6SJ.
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Best,
Will
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