On 8/7/06 at 10:33 AM Phil Clements wrote:
>> >Ian,
>> >Are you saying that a GDO can only dip a "circuit?"
>>
>> I'm saying you can't even have an L-C resonance without a circuit -
>> literally a closed, hard-wired loop.
>>
>> For example, if you simply connect an L and a C in series, with opposite
>> ends floating, you don't have a closed loop so you don't have a resonant
>> circuit yet. Before you can see a resonance and a dip, you must make
>> some other connection that closes the loop and completes the circuit.
>>
>> But the resonance then belongs to the entire circuit you have made - not
>> just the obvious inductor and capacitor, but also all the strays that
>> you don't know about.
>>
>> That requirement for a hard-wired circuit only begins to break down if
>> components are physically large enough to have significant
>> electromagnetic interactions between different parts of themselves -
>> antennas being the obvious example, and large anode chokes being
>> another.
>
>I agree with all of the above. Someone should have said this about 75 posts
>back to enlighten the multitudes of readers on the reflector. About 50% of
>the questions would not have had to be answered.
>
>Now here is the biggie that caused this thread....is the grid on a 3-500Z
>physically large enough to fall into "significant electromagnetic
>interaction" category, or is it in the "hard-wired" category, or none of
>the
>above?
Since there is interelectrode capacitance, stray capacitance, inductance, and
stray inductance in the circuit, yes I'd say there would be a resonance
somewhere.
We all know, or I think we all know, that a tube can go into self oscillation.
>
>(((73)))
>Phil Clements, K5PC
>
>
>
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Best,
Will
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