In most editions of the ARRL Amateur Radio Operator's Handbook there is a chart
that lists the resistance (usually per 1000 feet) of copper wire. To create a
resistor you just use this information to determine the length of wire needed.
Dividing 105.2 by 1000 gives a resistance of .1052 ohms per foot. You then
multiply this by 50 which gives a total length of 5.26 feet to achieve 50 ohms.
I would use a larger diameter wire (smaller gauge) which would result in more
wire being needed. However, the current handling capability would be increased.
Glen, K9STH
Website: http://k9sth.com
--- On Sun, 2/1/09, Bob Maser <bmaser@tampabay.rr.com> wrote:
I'm having a hard time finding a 50 ohm 50W resistor for a glitch resistor for
my 4CX1500B amp. Seems I remember that I could also use some AWG 30 for a
glitch. Can someone enlighten me?
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