> It can only rise if you RETUNE THE TANK CIRCUIT. The original
> question was about reducing drive WITHOUT RETUNING THE TANK CIRCUIT.
Bill, stop changing the question to suit your point of view.
The original question was about operating at the lower output
power level with the higher plate voltage. The only person
who ever said anything about not properly tuning the amplifier
for the operating power level was you.
I'm tired of your tactic of changing the question to suit your
yourself.
> -----Original Message-----
> From: amps-bounces@contesting.com
> [mailto:amps-bounces@contesting.com] On Behalf Of Bill, W6WRT
> Sent: Sunday, August 30, 2009 9:44 PM
> To: amps@contesting.com
> Subject: Re: [Amps] Loaded output circuits
>
>
> On Sun, 30 Aug 2009 11:27:39 -0600, John Lyles
> <jtml@losalamos.com> wrote:
>
> >Once a matching network
> >is built in metal or discrete components like capacitors & inductors
> >then it has a fixed transformation ratio, PERIOD.
>
> Correct, although W4TV disagrees.
>
>
> > If the operating point
> >of the active device (called 'plate impedance' for tubes)
> varies, this
> >network is no longer optimal.
>
> Correct
>
>
> > Reduction of drive power into a linear
> >amplifier changes Rp. If the plate voltage is reduced the
> proper amount
> >(this is easily calculated) then the same network becomes
> optimal again.
>
> Correct, but not relevant to the original question.
>
>
> >If no change is made, however, the network may no longer be
> terminated
> >in the proper R. As Joe explained, the circulating current can rise
> >significantly.
>
> It can only rise if you RETUNE THE TANK CIRCUIT. The original
> question was about reducing drive WITHOUT RETUNING THE TANK CIRCUIT.
>
> Certain keys on my keyboard are showing excessive wear,
> especially the ones that spell out WITHOUT RETUNING. What is
> it about the original question that makes everybody want to
> reduce power, RETUNE and then answer the question?
>
> 73, Bill W6WRT
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