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[Antennaware] Cylindrical Model for Triangular Tower

To: <antennaware@contesting.com>
Subject: [Antennaware] Cylindrical Model for Triangular Tower
From: btippett@alum.mit.edu (Bill Tippett)
Date: Tue, 21 May 2002 14:09:54 +0100
        Somewhere I got the following formula for a cylindrical
equivalent to triangular tower like Rohn 45.  

Equivalent Cylindrical Diameter = 2 * CUBEROOT [(D * F^2)/2]
 
where D = tube diameter and F = Face width.  For Rohn 45, D = 1.25" 
and F = 18", so cylindrical diameter equivalent = 11.7446"

        Does anyone know where this came from or if it is valid? 

                                                73,  Bill  W4ZV

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