[Antennaware] Cylindrical Model for Triangular Tower

[john.w1fv@telocity.com (John Kaufmann)]

Bill Tippett wrote: 

> 
> >     Somewhere I got the following formula for a
cylindrical
> > equivalent to triangular tower like Rohn 45.  
> > 
> > Equivalent Cylindrical Diameter = 2 * CUBEROOT [(D
* F^2)/2]
> >  
> > where D = tube diameter and F = Face width.  For
Rohn 45, D = 1.25" 
> > and F = 18", so cylindrical diameter equivalent =
11.7446"
> > 
> >     Does anyone know where this came from or if it is
valid? 


This formula originally appeared in the IEEE
Transactions on Broadcasting.  I posted a note about it
on this reflector back in 1998.  See:
http://lists.contesting.com/_antennaware/1998-October/000133.html.

73, John W1FV