Coax consists of three conductors: Center lead, inner shield, and
outer shield conducting surfaces.
The SWR of 1:1 refers to the shield inner surface current and the center
conductor current encountering no reactance, and the source impedance
being matched to the load impedance.
In normal operation the currents on center lead and inside the shield
are equal and opposite.
If the length of the coax makes a resonant structure such as an odd
multiple of a quarter wavelength, or if the coax is not lead away at
right angles to the antenna, current may be induced onto the outer
surface of the shield. Thus, the formerly balanced shield current will
divide between the inner of the shield and the outer surface, and shield
radiation may result.
Many hams forget that coax actually has THREE conductors as detailed above.
-Stuart Rohre
K5KVH
Marinus Loewensteijn wrote:
When Coax is terminated at the transmitter end and the far end with an
impedance that is equal to its defined impedance we will have a SWR of 1:1.
Only when the currents on inner conductor and on shield are equal and the
current / voltage nodes coincide at the same locations then they'll cancel
radiation.
If we have anything else that creates a SWR that is not 1:1 then waves will be reflected from the ends. Hence no longer will the current and voltage nodes be coinciding.
When nodes are no longer coinciding then we will have radiation.
What is wrong about this, what am I missing here?
Thanks, 73, marinus, ZL2ML
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