I need to know if there is a correct solution to transforming complex
impedances.
Assume a perfect 4:1 transformer at 1.83MHz. A load with R+/-j of 260 +330j
I am fairly certain that the R term just divides down to ~65ohms
(260/4=65). What happens with the j term?
To tune out the 330 ohms, a 264pf series capacitor is in order. If the j
term divides down to 82.5j, then a capacitor on the input side of 1000pf is
in order. If I had to choose, the 1000pf is less lossy and would be best
placed on the input side of the transformer. Right? Or am I missing
something...
Thanks for the feedback in advance.
Ford-N0FP
ford@cmgate.com
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