>At the posited high wind force, the 5/16" guy
>will put, say, 10,000 pounds of tension on the equalizer plate, which will
>rotate to "equalize". Since the holes in the plate are equally spaced about
>the pivot (anchor) hole, equal force will be exerted on the 3/16" guy, far
>exceeding its rated capacity.
It would seem to me that the rotational force applied to the smaller guy
would be far less than the direct force applied to the anchor.
I am obviously missing something somewhere.
73, Dick
--
Dick Flanagan W6OLD CFII Minden, Nevada
Visit http://www.delphi.com/electronic/
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