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Re: [TowerTalk] inverted vee

To: Herbert Schoenbohm <herbert.schoenbohm@gmail.com>, "towertalk@contesting.com" <towertalk@contesting.com>
Subject: Re: [TowerTalk] inverted vee
From: Jim Hoge <knowkode@verizon.net>
Reply-to: Jim Hoge <knowkode@verizon.net>
Date: Fri, 6 Nov 2015 17:10:48 +0000 (UTC)
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
Herb, 

Maybe not transposed but not clear. I was showing the difference and assumed 
that it was understood that the difference is what was needed to be added to 
the antenna to lower its resonant frequency. The final comment was a suggestion 
to start with, say 25" when it called for 22" and trim as needed.
73,Jim W5QM
 


     On Friday, November 6, 2015 10:56 AM, Herbert Schoenbohm 
<herbert.schoenbohm@gmail.com> wrote:
   

 Actually if you are going lower in frequency you add wire not reduce 
wire....so the formula results appear transposed.

Herb, KV4FZ

On 11/6/2015 12:27 PM, Jim Hoge wrote:
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>  
>
>
>
> The theory says....
> f(mHz)/234=length in feet of each dipole leg
>
> so
> 234/3.615=66.57
> and
> 234/3.515=64.73
> the difference is
> 66.57-64.73=1.84 feet or 22 inches
> Start a bit longer and trim as needed.
>
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