On Sat, Apr 02, 2005 at 11:38:10AM -0500, Gene WØQFC wrote:
> My logging program requires that I enter the lat & long figures as:
>
> 28.xxxxxx and -82.xxxxxx.
>
> I have the figures from my GPS receiver but they are expressed as:
>
> 28.27.319 N
> _82.36.623.W
>
> How do I convert the above to the 28.xxxxxx format?
> Thanks in advance.
>
> Gene, WØQFC
> Spring Hill, FL
>
I suspect that what it means is 28 deg, 27.319 min N and 82 deg, 36.623
min W. Since there are 60 minutes in a degree, that becomes:
28 + 27.319/60 deg = 28.45531667 deg and
82 + 36.623/60 deg = 36.61038333 deg
73,
Bob, N7XY
_______________________________________________
See: http://www.mscomputer.com for "Self Supporting Towers", "Wireless Weather
Stations", and lot's more. Call Toll Free, 1-800-333-9041 with any questions
and ask for Sherman, W2FLA.
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