[AMPS] Re: Input Impedance... units??

George T. Daughters gdaught6@leland.Stanford.EDU
Tue, 24 Mar 1998 08:27:58 +0008


hi all,

> >Since input impedance equals drive power divided by peak 
> >cathode current squared, you can see how the input impedance
> >stays fairly close throughout the operating range.

this has the correct units (ohms) at least 

> >The input impedance is the ratio of input drive power to peak 
> >cathode current.

and this has the units of potential (volts), not impedance!

73,
George T. Daughters, K6GT

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