[AMPS] Diodes

measures 2@vc.net
Wed, 23 Feb 2000 08:51:35 -0700


>
>Rich says:
>
>>Without equalization,  the 250v reverse surge happily divides unequally. 
>>Approx. 101v is dropped acrosss the 101v diode and approx. 149v is 
>>dropped across the 190v diode.  
>
>Not if the diode capacities are equal. 

the resistance of the equalizers is not a factor? 

>Two equal diode capacities will
>attempt to split the voltage equally. The  probability is that they aren't
>equal, though. 

A safe wager.  .  . 

>Frequency has nothing to do with it, 

The 10k-ohm "equalizer" resistances seem to be in the driver's seat.  

>since voltage division
>across series capacitors is in the ratio of the capacities - even at DC.
>
cheers, Peter

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