[AMPS] Diodes
measures
2@vc.net
Wed, 23 Feb 2000 08:51:35 -0700
>
>Rich says:
>
>>Without equalization, the 250v reverse surge happily divides unequally.
>>Approx. 101v is dropped acrosss the 101v diode and approx. 149v is
>>dropped across the 190v diode.
>
>Not if the diode capacities are equal.
the resistance of the equalizers is not a factor?
>Two equal diode capacities will
>attempt to split the voltage equally. The probability is that they aren't
>equal, though.
A safe wager. . .
>Frequency has nothing to do with it,
The 10k-ohm "equalizer" resistances seem to be in the driver's seat.
>since voltage division
>across series capacitors is in the ratio of the capacities - even at DC.
>
cheers, Peter
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