[AMPS] basic question about dipping the plate

[jeff millar]

I like my answer better.  Because it answers a basic question in a basically
correct way.

Besides, where do you get the idea that an L network at resonance is a dead
short?

jeff, wa1hco

----- Original Message -----
From: measures <2@vc.net>
To: AMPS <amps@contesting.com>
Sent: Sunday, April 22, 2001 12:33 PM
Subject: Re: [AMPS] basic question about dipping the plate


>
> >
> >The output network becomes parallel resonant at dip and parallel resonant
> >circuits have their highest impedance at resonance.  Off resonance, the
tune
> >cap and inductor look like shunts to ground and the tube has to try to
work
> >into a lower impedance...thus the high current.
>
> ?  Murphy said that things are more complicated than they look.  A
> pi-network is two L-networks in series.  At resonance, an L-network is a
> dead short.  Thus, L-networks are not oprated at resonance.  When my
> SB-220 is tuned for max output on 3820KHz, a dipmeter shows that the tank
> resonates several hundred KHz lower.  Pi-networks are not like parallel
> resonant tanks in days of yore.
>
> cheers, Jeff
>
> -  Rich..., 805.386.3734, www.vcnet.com/measures.
> end
>
>
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>


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