[AMPS] basic question about dipping the plate

[Michael Tope]

Rich,

I believe that is only true if there is no load connected across the shunt side of the L-network. 
In that case the L-network simply becomes a hi-q series resonant trap to ground (e.g. a near
dead short). Connect a finite resistive load across the shunt element and that is no longer true.
Under this condition, the currents through the inductor and capacitor are no longer equal. Thus 
their respective voltage drops are no longer in anti-phase (e.g. no more dead short).

73 de Mike, W4EF.....................

> ?  Murphy said that things are more complicated than they look.  A 
> pi-network is two L-networks in series.  At resonance, an L-network is a 
> dead short.  Thus, L-networks are not oprated at resonance.  When my 
> SB-220 is tuned for max output on 3820KHz, a dipmeter shows that the tank 
> resonates several hundred KHz lower.  Pi-networks are not like parallel 
> resonant tanks in days of yore.  
> 
> cheers, Jeff



--
FAQ on WWW:               http://www.contesting.com/FAQ/amps
Submissions:              amps@contesting.com
Administrative requests:  amps-REQUEST@contesting.com
Problems:                 owner-amps@contesting.com