[Amps] Watts to DBM??

[Jim Forsyth]

Output Power = 100((2x2)/(.6x.6)) = 1111 Watts

Jim, AF6O

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From: "Steve Flood" <kk7uv at bresnan.net>
Sent: Monday, October 05, 2009 3:59 AM
To: <amps at contesting.com>
Subject: Re: [Amps] Watts to DBM??

> So, I am using an oscilloscope with an RF sampler to measure output power.
>
> With barefoot 100 watts, I read 0.6 volts p-p on the scope.
> With the amp in line, I read 2.0 volts p-p on the scope.
> What is my output power?
>
> 20 log (2.0/0.6) = 10.46 dB
>
> I divide 10.46 dB by 10 and get 1.46 dB.
> I take 10 to the 1.46 power and get 11.11.
> I multiply by 100 and get 1111 watts output.
>
> Is that correct?
>
> Steve, KK7UV
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