[Amps] Watts to DBM??

[Bill, W6WRT]

ORIGINAL MESSAGE:

On Mon, 5 Oct 2009 04:59:41 -0600, "Steve Flood" <kk7uv at bresnan.net> wrote:

>Is that correct?

REPLY:

Yes, although there is an easier way.  The power ratio is the square of the
voltage ratio, provided the impedance is the same. 

 Just divide the voltages to get a ratio (3.33333 in this case), square the
ratio (11.11) and multiply the power by that. 

73, Bill W6WRT