[Amps] Advice needed for SS amp

[Larry Benko]

Jim,

I have done this calculation several times so maybe someone else will do 
it as verification.  Using the temperature rise I posted and your 
example of 1500W & 1/2 gal. water starting at 50deg F would boil in 
(2000/1500)*(1/2)*(162/13.7) = 7.88 min. (not the 11.8 min. you 
calculated).  Maybe you are boiling a little less than 1/2 gallon, or 
your heater is a little higher than 1500W or the initial water temp is a 
little higher than 50 deg. F or maybe I made a mistake.

I would bet on the 1500W heater which is probably rated for 120/240V or 
117/234V and most line voltages today have risen to 125/250V. 117V to 
125V change would change the 1500W heater into a 1712W heater.

Any one want to check my math?

Larry, W0QE

On 6/6/2013 10:58 AM, Jim Thomson wrote:
> Date: Thu, 06 Jun 2013 08:24:58 -0600
> From: Larry Benko <xxw0qe at comcast.net>
> To: amps at contesting.com
> Subject: Re: [Amps] Advice needed for SS amp
>
> 2000W of power(heat) into 1 gallon of pure water raises the temperature
> 7.7deg. C (13.7deg. F) per minute.  Anything you do to water such as
> mixing in alcohol reduces the cooling capacity somewhat.  In a total
> loss system where the water would be run through the amp and then out
> into the garden a flow of 1 quart (or ~ 1 liter) per minute would suffice.
>
> Larry, W0QE
>
> ##  are you sure about that ?   IF the cold tapwater was 50 F, it would take 11.8 mins to reach
> boiling.   It does not take more than 5 mins to boil  1/2 gallon of water in my 1500 w kettle.
>
> Jim   VE7RF
>
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