Topband: Ground Radial Discussion
k8bhz at alphacomm.net
k8bhz at alphacomm.net
Sat Oct 28 10:59:21 EDT 2017
I've taken the liberty of opening a new thread, which I probably should
have done before.
To Dan, AC6LA,
First let me also thank you for your civil replies. As you stated,
"Refreshing in this internet age".
I think I have a simple comparison to show the problem, using the 1/4 WL
Vertical (36 ohms R radiation) and 1 kW rf.
First, consider antenna operating over the perfect ground plane. All the
power is radiated. P = I sq X R radiation. So, I = 5.27 Amps.
Then, let's replace the perfect ground with an 8' ground rod, which in
my soil is about 100 ohms.
Now the antenna feed impedance is R radiation + R ground, or 36 + 100 =
136 ohms. Then apply our 1 kW. I is now down to 2.71 Amps. Radiated RF
power is now 264.7 W & 735.3 W goes into heating the ground. This
illustrates two things. One, why we don't use a ground rod, but more
importantly, when R ground increases, using constant power, the current
and efficiency drop.
Let's just see how much power is required if we were to achieve the same
ground current as the perfect ground model. As the I squared term would
be identical, the power required would simply be the ratio of
impedances, or P = 1 kW (136/36) = 3.78 kW!
Now, realizing that the electrical 1/4 WL radials present the lowest R
ground to the antenna, you can see that greatest efficiency is to be had
there. Likewise, with 1/2 electrical WL radials, R ground is the
highest, so efficiency is the worst.
In Rudy's discussion of a constant current into the radials (and that
current MUST be the same into the vertical), the RADIATED power is
constant. However the ground losses vary considerably. As the radial
resistance increases when exceeding 1/4 electrical WL, Power input must
be increased to achieve the same current. Importantly, as the radials
are now not being fed at a current maximum, but elsewhere on the
sinusoidal pattern, larger values will be observed elsewhere along the
radials, increasing their losses.
Hope that helps...
Brian K8BHZ
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