[TowerTalk] Connector Loss Question

[N7KA at comcast.net]

Here is some differnt info.

http://www.amphenolrf.com/products/typen.asp?N=0&sid=48B3478041F8E17F


-------------- Original message -------------- 
From: Steve Hunt <steve at karinya.net> 

> Joe, 
> 
> Sorry to "nit pick", but if your formula is correct and the constant is 
> 0.5, shouldn't the loss be 0.57dB? It makes a big difference if you have 
> several connectors in the chain. 
> 
> 73, 
> Steve G3TXQ 
> 
> 
> Joe Reisert, W1JR wrote: 
> > Hi Manius, 
> > 
> > The insertion loss of a good N connector is equal to the square root 
> > of F (in GHz) times a constant (K). 
> > 
> > The constant for a single N connector is 0.5. Therefore, at 23 CM 
> > (1.3 GHz) the loss is approximately .057 dB so you can add up the 
> > losses based on your situation. 
> > 
> > 73, 
> > 
> > Joe, W1JR 
> > 
> > 
> > 
> 
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