[TowerTalk] Universal Tower questions
K8RI-on-TowerTalk at tm.net
Thu Jul 23 01:31:34 PDT 2009
John Kemker wrote:
> Okay, so what's the formula to determine the adjusted wind load? Is
> it straight multiply the wind load of the antenna by the height, in
> feet, above the tower?
With the rotator mounted down in the tower that would be a good
approximation. You don't have to go up very far above the top of the
tower before the extra load gets quite large.
> but for most conditions that is a minimum as load multiplied by height
> above top of tower equals the load added to the top of the tower.
Just add the load presented by the antenna mounted at the top of the
tower to that figure. The tower wind loading is already figured into
the tower specs for a given height, usually with one coax mounted per leg.
> Roger (K8RI) wrote:
>> John Kemker wrote:
>>> All I'm planning on putting up on the tower is a Mosley CL-33 and a
>>> W5WVO-modified Cushcraft A5-50 on top of a 15 ft. 2" dia. mast,
>> Don't forget to multiply the wind load of the A5-50 by the height
>> above the tower.
>> Roger (K8RI)
>>> by a Yaesu G1000SDX. Single run of LD5-50F out to tower with a coax
>>> switch up near the top to switch between the two beams. I *might*
>>> top it off with a 10m vertical, but then again, might just put that
>>> somewhere else, like on the house.
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