[TowerTalk] tuners and power rating

[Steve Hunt]

Jim,

I disagree!

If we restrict ourselves to talking about the series-form complex load 
impedance, the reactive component will *not* affect the current required 
through the load for a particular power dissipation. For example, to 
dissipate 150W in a load of 150+j0 you need a current of 1A; you also 
need the same 1A if you want to dissipate 150W in a load of 150+j1000.

Once you start talking about parallel components, things are different. 
Your example of a 150 Ohm resistor in parallel with a 150 Ohm inductor 
represents a load of 75+j75 Ohms - the resistive part is no longer 150 Ohms.

73,
Steve G3TXQ



On 01/12/2010 04:14, jimlux wrote:
>
> The current could be higher or lower.  Say you've got a 150 ohm resistor
> in parallel with a 150 ohm inductor.  The current that flows through the
> inductor also flows through the feedline, and contributes to the loss.
>
> Or, if you've got the resistor and inductor in series.  Now the current
> flow will be even less. (by a factor of 70%).
>
> that's the difference between apparent power (Irms * Vrms) and active
> and reactive power.
>
>