> >Since input impedance equals drive power divided by peak
> >cathode current squared, you can see how the input impedance
> >stays fairly close throughout the operating range.
this has the correct units (ohms) at least
> >The input impedance is the ratio of input drive power to peak
> >cathode current.
and this has the units of potential (volts), not impedance!
George T. Daughters, K6GT
FAQ on WWW: http://www.contesting.com/ampfaq.html
Administrative requests: amps-REQUEST@contesting.com