At 01:29 PM 3/24/98 -0000, you wrote:
>>Since input impedance equals drive power divided by peak
>>cathode current squared, you can see how the input impedance
>>stays fairly close throughout the operating range.
>>The input impedance is the ratio of input drive power to peak
>So which one is it?
One is the formula and the other is the explanation. I cannot
type math symbols on this keyboard! Sorry.
>>When you come up with a value from the above formula, you
>>can then substitute a non-inductive resistor of the calculated
>>value for the tube and use your noise bridge or MFJ analyser
>>to park your tuned input in the middle of the band.
>I wouldn't substitute, but put in parallel.
As long as the tube ain't lit or is in cuttoff, it makes no
difference. I usually have this chore done before I take the tube
out of the box!
"To do is to be".....Sartre
"To be is to do".....Aristotle
"To be or not to be".Shakespere
"Do be do be do".....Sinatra
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