>Since input impedance equals drive power divided by peak
>cathode current squared, you can see how the input impedance
>stays fairly close throughout the operating range.
>The input impedance is the ratio of input drive power to peak
So which one is it?
>When you come up with a value from the above formula, you
>can then substitute a non-inductive resistor of the calculated
>value for the tube and use your noise bridge or MFJ analyser
>to park your tuned input in the middle of the band.
I wouldn't substitute, but put in parallel.
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