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[AMPS] WWQuiz - anyone go to work today ?.

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Subject: [AMPS] WWQuiz - anyone go to work today ?.
From: phil@vaxxine.com (Phil T. (VA3UX))
Date: Mon, 04 Oct 1999 21:50:22
Judging from the 50+ messages from this reflector today, I'd say a couple
of you (and you know who you are) didn't leave the house for work today.
All wound-up with SWR are we ?

Phil

At 01:16 AM 10/5/99 +0100, you wrote:
>
>At 07:35 PM 10/4/99 -0500, bob alexander wrote:
>...
>
>>Hi Rich,
>>I think the main problem here is a lack of understanding as to what a
>>standing wave is.  It is simply a voltage or current on a line that
>>changes amplitude  as you move from one end of the line to the other. 
>>This is due to the Z mismatch at the load/transmission line junction.
>>Using your example of a 50 ohm load & 93 ohm line:
>>with 100 watts output from the generator the voltage at the generator
>>end of the 93 ohm 1/2 wavelength line will be 70.71 volts @ 1.414 amps.
>>ExI = 100  E/I = 50 ohms.
>>
>>At the 1/4 wavelength point on the line the voltage will be 131.52 volts
>>@ .77 Amps and 90 dgr phase angle.  The Z at this point on the line is
>>172.98 ohms...  eI=100  e/i= 172.98 ohms and the max E/ min E =
>>131.52/70.71 = 1.86 = VSWR
>>
>>At the antenna end of the line the voltage is again 70.71 v and the
>>current is 1.414 Amps  which gives 100 watts and 50 ohms.  93 ohm
>>feedline / 50 ohm load = 1.86:1 SWR.
>>
>>So, The Z looking into the cable is simply the voltage / current at that
>>point on the line.  If you measure the voltage and current and
>>associated phase angles with a scope and the appropriate probes you will
>>see a single voltage and a single current at each measurement point.
>
>My compliments, Bob, for adding some substance on this topic after 2 days
>of non-stop sniping back and forth among 3 or maybe 4 individuals.  Guys,
>nobody else cares about this tit-for-tat stuff.  Enough, already -- back to
>amps, puleeze!
>
>73, Pete Smith N4ZR
>n4zr@contesting.com 
>
>Sometimes a tower is just a tower
>
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>
>
>

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