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[AMPS] basic question about dipping the plate

To: <amps@contesting.com>
Subject: [AMPS] basic question about dipping the plate
From: 2@vc.net (measures)
Date: Tue, 24 Apr 2001 06:46:04 -0700
>
>
>> >
>> >Rich has his own definition of "resonant".
>> >
>> ?  When XL = XC, a series or a parallel circuit is resonant.  For series 
>> circuits at resonance, R is virtually zero.  For parallel circuits, R is 
>> virtually infinite at resonance.  
>> 
>
>Yes, agreed. But the loaded L-network is neither a true series nor true 
>parallel network. The impedance ratio of the resonant L network (Xc=Xl)
>will not be infinite because there is a resistive load across the shunt
>element. In this case, the currents through two reactive elements can't be 
>equal and the resulting voltages drops will not be in antiphase as in
>the classic series resonant tank. 
>
>Just to give you the benefit of the doubt, I plugged some real numbers 
>into my circuit simulator (Ansoft Serenade SV). With 10uH series L and 100pF 
>shunt C and a 2000 ohm termination across the shunt C, I get an input 
>impedance 
>of 50 + j 8 ohms at the resonant frequency (5.03 MHz). At this frequency 
>Xl = 316 and Xc = 316 ohms. This is hardly a dead short. Of course, when I 
>place an open circuit across the shunt C, the network becomes a classic 
>series tank and the input impedance at 5.03 MHz drops to 0 ohms. 
>
thanks,  Mike
>
>
>
>--
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>
>


-  Rich..., 805.386.3734, www.vcnet.com/measures.  
end


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