>
>If I require a 1750 volt power supply for an amplifier
>that loaded will draw 1 amp of current how do I
>account for the peak voltage (1750 x 1.414). In other
>words the 1750 volts will peak at a little over 2400
>volts unloaded and this is what the capacitors will
>charge up to. If the tubes are max rated for 1750
>volts then I would be supply too much voltage to them
>when they were not drawing significant current. Does
>this mean I need a lower voltage transformer to
>account for the peaks and just make sure this
>transfomer's VA rating can supply the load without an
>excessive voltage drop?
/\ The anode peak V is normally c. 1.9 X the supply V during max RF
signal. Thus, the anode no-load V can be somewhat higher than the AØ
rating. An example is the 8171. Even though the anode rating is
7500v-max, 10kV in standby is ok.
cheers, Bill
- R. L. Measures, 805.386.3734,AG6K, www.vcnet.com/measures.
end
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