That's probably close enough for this sort of work!
But it's maybe worth pointing out that an unmatched line does not have
uniform losses along its length - the losses are higher at the standing
wave current maxima than they are at the minima. On a line with an SWR
of 6:1 the losses at the current maxima will be 36 times those at the
minima. So, for accurate calculations on an unmatched line, you can't
simply scale the losses linearly with length.
73,
Steve G3TXQ
On 09/08/2013 13:55, Joel Hallas wrote:
Steve,
For purposes of comparison to the 100 foot length
Bob and I used, I would remind folks to multiply your attenuation by 1.7.
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