>
>Since I'm wearing egg anyway, more can't hurt.
>
>1. Smith Chart says 1/2 wave cable brings you all the around back to
>the original load impedance (50 ohms, here). Therefore the black box of
>the cable/load looks like 50 ohms, so, all should be happy. I say the
>VSWR is 93/50 = 1.86:1 - this caused by the mismatch at the load end.
? You have 50 +/- j0 ohms at the position of the SWR meter, and it reads
1.86:1? I don't see how, Mike.
>2. I'd like to know this one. 2.63? SQRT( 2 * (1.86 ^ 2))
>
>Mike
>N2MG
>
>On Sunday, October 03, 1999 1:27 AM, measures [SMTP:measures@vcnet.com]
>wrote:
>> Questions 1 and 2:
>>
>> A 50-ohm termination is connected to a generator through a one-half
>> wavelength, 93 ohm characteristic-Z coaxial cable.
>>
>> What is the SWR as measured at the generator with a 50-ohm
>> characteristic-Z SWR meter?
>>
>> What is the SWR with a 93-ohm characteristic-Z SWR meter?
>>
>> - Rich..., 805.386.3734, www.vcnet.com/measures.
>
>
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- Rich..., 805.386.3734, www.vcnet.com/measures.
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