>
>On Tuesday, October 05, 1999 1:53 AM, measures [SMTP:measures@vcnet.com]
>wrote:
>> >
>> >Since I'm wearing egg anyway, more can't hurt.
>> >
>> >1. Smith Chart says 1/2 wave cable brings you all the around back to
>> >the original load impedance (50 ohms, here). Therefore the black box of
>> >the cable/load looks like 50 ohms, so, all should be happy. I say the
>> >VSWR is 93/50 = 1.86:1 - this caused by the mismatch at the load end.
>>
>> ? You have 50 +/- j0 ohms at the position of the SWR meter, and it reads
>> 1.86:1? I don't see how, Mike.
>>
>
>Rich, this says that as long as I have a multiple-half-wave of cable,
>the impedance of the cable plays no part in the SWR.
ok
>If this were true, what happens to the standing waves that are created
>at the load end ( 93 ohm cable, 50 ohm load )?
>Why would connecting an SWR meter to the near end eliminate them?
It eliminates reflections only at the halfwave point.
>
Cheers, Mike
>
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- Rich..., 805.386.3734, www.vcnet.com/measures.
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