On Tuesday, October 05, 1999 1:53 AM, measures [SMTP:measures@vcnet.com]
wrote:
> >
> >Since I'm wearing egg anyway, more can't hurt.
> >
> >1. Smith Chart says 1/2 wave cable brings you all the around back to
> >the original load impedance (50 ohms, here). Therefore the black box
of
> >the cable/load looks like 50 ohms, so, all should be happy. I say
the
> >VSWR is 93/50 = 1.86:1 - this caused by the mismatch at the load end.
>
> ? You have 50 +/- j0 ohms at the position of the SWR meter, and it
reads
> 1.86:1? I don't see how, Mike.
>
Rich, this says that as long as I have a multiple-half-wave of cable,
the impedance of the cable plays no part in the SWR.
If this were true, what happens to the standing waves that are created
at the load end ( 93 ohm cable, 50 ohm load )?
Why would connecting an SWR meter to the near end eliminate them?
Mike
N2MG
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