I like my answer better. Because it answers a basic question in a basically
correct way.
Besides, where do you get the idea that an L network at resonance is a dead
short?
jeff, wa1hco
----- Original Message -----
From: measures <2@vc.net>
To: AMPS <amps@contesting.com>
Sent: Sunday, April 22, 2001 12:33 PM
Subject: Re: [AMPS] basic question about dipping the plate
>
> >
> >The output network becomes parallel resonant at dip and parallel resonant
> >circuits have their highest impedance at resonance. Off resonance, the
tune
> >cap and inductor look like shunts to ground and the tube has to try to
work
> >into a lower impedance...thus the high current.
>
> ? Murphy said that things are more complicated than they look. A
> pi-network is two L-networks in series. At resonance, an L-network is a
> dead short. Thus, L-networks are not oprated at resonance. When my
> SB-220 is tuned for max output on 3820KHz, a dipmeter shows that the tank
> resonates several hundred KHz lower. Pi-networks are not like parallel
> resonant tanks in days of yore.
>
> cheers, Jeff
>
> - Rich..., 805.386.3734, www.vcnet.com/measures.
> end
>
>
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