>
>I like my answer better. Because it answers a basic question in a basically
>correct way.
>
>Besides, where do you get the idea that an L network at resonance is a dead
>short?
>
? In an L network, C and L are connected in series. For a series
circuit to be resonant, XL must = XC. This is a virtual short.
cheers, Jeff.
>
>----- Original Message -----
>From: measures <2@vc.net>
>To: AMPS <amps@contesting.com>
>Sent: Sunday, April 22, 2001 12:33 PM
>Subject: Re: [AMPS] basic question about dipping the plate
>
>
>>
>> >
>> >The output network becomes parallel resonant at dip and parallel resonant
>> >circuits have their highest impedance at resonance. Off resonance, the
>tune
>> >cap and inductor look like shunts to ground and the tube has to try to
>work
>> >into a lower impedance...thus the high current.
>>
>> ? Murphy said that things are more complicated than they look. A
>> pi-network is two L-networks in series. At resonance, an L-network is a
>> dead short. Thus, L-networks are not oprated at resonance. When my
>> SB-220 is tuned for max output on 3820KHz, a dipmeter shows that the tank
>> resonates several hundred KHz lower. Pi-networks are not like parallel
>> resonant tanks in days of yore.
>>
>> cheers, Jeff
>>
>> - Rich..., 805.386.3734, www.vcnet.com/measures.
>> end
>>
>>
>> --
>> FAQ on WWW: http://www.contesting.com/FAQ/amps
>> Submissions: amps@contesting.com
>> Administrative requests: amps-REQUEST@contesting.com
>> Problems: owner-amps@contesting.com
>>
>>
>
>
>--
>FAQ on WWW: http://www.contesting.com/FAQ/amps
>Submissions: amps@contesting.com
>Administrative requests: amps-REQUEST@contesting.com
>Problems: owner-amps@contesting.com
>
>
- Rich..., 805.386.3734, www.vcnet.com/measures.
end
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FAQ on WWW: http://www.contesting.com/FAQ/amps
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