To: | peter.chadwick@Zarlink.Com |
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Subject: | Re: [Amps] Equalising resistors with HV diodes |
From: | R.Measures <r@somis.org> |
Date: | Mon, 20 Sep 2004 07:36:16 -0700 |
List-post: | <mailto:amps@contesting.com> |
On Sep 20, 2004, at 6:08 AM, peter.chadwick@Zarlink.Com wrote:
- Is not current equal through each element in a series circuit? Does it make sense to fix something that is not broken? the reverse voltage - As the avalanche potential is approached. reverse leakage-I increases and tends to limit V. Thus, the reverse potential that appears across each rectifier in a series string is proportional to its reverse potential capability -- provided that the reverse current maximum is not exceeded. *** note -- for 3A units - such as the 1N5408, this is c. 5uA. With resistors, the voltage distribution across the diodes is fixed by the resistor ratios. - Which un-equalizes the previously equal reverse current in each diode in the string.
- C-equalization? Another is the reverse recovery time. - probably not significant for 50-60z? - Which is why is why I measure the PIV of the diodes I buy. cheerz, Peter Richard L. Measures, AG6K, 805.386.3734. www.somis.org _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps |
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