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Re: [Amps] Equalising resistors with HV diodes

To: peter.chadwick@Zarlink.Com
Subject: Re: [Amps] Equalising resistors with HV diodes
From: R.Measures <r@somis.org>
Date: Mon, 20 Sep 2004 07:36:16 -0700
List-post: <mailto:amps@contesting.com>

On Sep 20, 2004, at 6:08 AM, peter.chadwick@Zarlink.Com wrote:






Rich said:

Please explain why equalizing resistors have merit.

Because if the reverse leakage differs between diodes,

- Is not current equal through each element in a series circuit? Does it make sense to fix something that is not broken?


the reverse voltage
distribution also differs. The one with the least leakage ends up with the
highest voltage across it, which could exceed the breakdown volts.

- As the avalanche potential is approached. reverse leakage-I increases and tends to limit V. Thus, the reverse potential that appears across each rectifier in a series string is proportional to its reverse potential capability -- provided that the reverse current maximum is not exceeded. *** note -- for 3A units - such as the 1N5408, this is c. 5uA.


With
resistors, the voltage distribution across the diodes is fixed by the
resistor ratios.

- Which un-equalizes the previously equal reverse current in each diode in the string.

If the capacitances aren't matched, that will also affect the voltage
distribution. That's one reason why it is not wise to mix diodes of the
same nominal type from different manufacturers without some equalisation.

- C-equalization?


Another is the reverse recovery time.

- probably not significant for 50-60z?

Experience also suggests that for best reliability, buy diodes from
reputable manufacturers - some of the far Eastern ones are distinctly dodgy
froma reliability viewpoint.



- Which is why is why I measure the PIV of the diodes I buy.

cheerz, Peter

Richard L. Measures, AG6K, 805.386.3734. www.somis.org

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