----- Original Message -----
From: "R L Measures" <r@somis.org>
>>> shows that it is resonant about 7% lower in frequency.
>>> If an L-network was resonant on the operating frequency,
>>> infinite current would flow through it because the reactive
>>> components are equal, opposite, in series, and not in parallel.
>>
>> Rich,
>> Unless the effective parallel R across each component is zero,
>> this can't happen.
>
> What caused the dip?
>
Even a resonant circuit with finite loaded Q will store energy
and cause a dip. There is no need to invoke an infinite Q
resonance to have a dip.
73, Mike W4EF........................................
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