Rick,
I already corrected this misunderstanding once: for a 2:1 SWR the
maximum voltage will be 1.414 times the matched voltage, not double! The
minimum voltage will be 0.707 times the matched voltage.
If V is the matched line voltage, Vmax=1.414xV and Vmin=V/1.414 giving
Vmax/Vmin=2:1
Steve G3TXQ
On 02/08/2014 19:00, Richard (Rick) Karlquist wrote:
For 2:1 VSWR, 2X is the worst case, which you would want to use for
design. In practice, it could vary from half to twice the matched
value for a short section of line.
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