On 8/2/2014 1:10 PM, Steve Hunt wrote:
Rick,
I already corrected this misunderstanding once: for a 2:1 SWR the
maximum voltage will be 1.414 times the matched voltage, not double! The
minimum voltage will be 0.707 times the matched voltage.
If V is the matched line voltage, Vmax=1.414xV and Vmin=V/1.414 giving
Vmax/Vmin=2:1
Steve G3TXQ
Yes, we all know this, but power loss is proportional to the
SQUARE of the voltage, so it is doubled for 2:1 SWR in the worst
case. Am I missing something?
Rick N6RK
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