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[VHFcontesting] Calculating distances from grid squares

To: VHF Contesting Reflector <vhfcontesting@contesting.com>
Subject: [VHFcontesting] Calculating distances from grid squares
From: James Duffey <jamesduffey@comcast.net>
Date: Thu, 14 Apr 2016 22:16:42 -0600
List-post: <vhfcontesting@contesting.com">mailto:vhfcontesting@contesting.com>
Some have asked how the distance between the two grid squares are calculated. 

Here is one way that the distance between the six grid squares is calculated:

The calculation starts by converting the 6 grid square center to a latitude and 
longitude. You can find the technique for doing that here:

Tyson, N5JTY, Conversion Between Geodetic and Grid Locator Systems, QST January 
1989, pp. 29-30, 43

or there are several online calculators that will do that for you. 

Then, using high school trigonometry, the distance between the two points can 
be calculated:

d = arccos(sin φ1 ⋅ sin φ2 + cos φ1 ⋅ cos φ2 ⋅ cos Δλ ) ⋅ R 

where d is the distance between the two lat-lon points, R is the radius of the 
earth, φ1 and φ2 are the latitudes of the two points, and Δλ is the difference 
in longitude between the two points. Angles are in radians. 

The earth is not quite a sphere and there are factors which can be added to 
that calculation to make it more precise. There is some dependence on the datum 
which is used in the calculation, but both these effects are probably small 
compared to the distance to the center of the 6 square grid that is ignored in 
the scoring calculation.

I don’t know whether or not the ARRL will use this exact method, but it will 
use something not too different. I hope that this helps. - Duffey KK6MC
--
KK6MC
James Duffey
Cedar Crest NM





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