C42 is a shunt component on the *input* side of the LPF - the voltage
across it is the full output voltage of the four combined PA modules,
fundamental plus harmonics.
At 14MHz it's reactance is 114 Ohms. The current it flows is given by
simple Ohm's law: I=Vout/114 irrespective of what else is in parallel
with it.
Steve G3TXQ
On 27/08/2013 22:05, Phil Chambley, Sr. wrote:
Those capacitors are a part of the shunt components in the low pass
filter network. They are not passing all of the current generated by
the amplifier. They are passing only that part of the harmonic energy
that makes it that far through the filter, and then only half of that,
since there are two of them in parallel. Without drowning in
arithmetic, I suggest that a good quality ceramic disc will probably
be adequate.
Phil C. Sr.
k4dpk
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